Question

Hallar el valor de "y", si: 1 + 3 + 5 + 7 +... + (2y+3) = 289

PORFA NO RESPONDAN SI NO SABEN

Answer 1

Respuesta:

1 + 3 + 5 + 7 +... + (2y+3) = 289   y = 135

Answer 2

Verified answer

SERIES NOTABLES

Fórmula:

[tex]1+3+5+7+...+(2n-1)=n^{2} \\[/tex]

Problema:

[tex]1 + 3 + 5 + 7 +... + (2y+3) = 289[/tex]

Igualamos:

[tex]2n-1=2y+3\\2n=2y+3+1\\2n=2y+4\\n=y+2[/tex]

[tex]n^{2} =289\\n=17[/tex]

[tex]y+2=17\\y=15[/tex]