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Por pitagoras Hallamos el valor de L²
L² +(√3)² = (2L)²
L² + 3 = 4L²
3 = 4L² - L²
3 = 3L²
3/3 = L²
1 = L
El area es 2 veces el area del triangulo formado:
A = (2a.L)/2
A = 2(√3)(1)/2 --->Simplificamos 2
A = √3 Rtaaaaaaaaaaaaaaa