Question

HALLAR =1545°+245°+ √2 45°

Halla el valor de “b” en la siguiente igualdad: b.csc53° = sen37° + cot53°

Answer 1

Explicación paso a paso:

1.- Cot beta = 3/1

[tex] = { \cot}^{2} \beta - 5 \\ = {( \frac{3}{1}) }^{2} - 5 \\ = 9 - 5 \\ = 4[/tex]

2. N = 9×sec○×cot○

[tex]n = 9 \times \sec( \alpha ) \times \cot( \alpha ) \\ = 9 \times \frac{41}{40} \times \frac{40}{9 } \\ = \frac{9}{9} \times \frac{40}{40} \times 41 \\ = 41[/tex]

3.-

[tex] { \cot}^{2} 30 - 4y = 7y - { \sec}^{3} 60 \\ { \sqrt{3} }^{2} - 4y = 7y - {2}^{3} \\ 3 - 4y = 7y - 8 \\ 11 = 11y \\ 1 = y[/tex]