Explicación paso a paso:
[tex]5 < 2x + 7 \leqslant 15 \\ 5 - 7 < 2x + 7 - 7 \leqslant 15 - 7 \\ - 2 < 2x \leqslant 8 \\ \frac{ - 2}{2} < \frac{2x}{2} \leqslant \frac{8}{2} \\ - 1 < x \leqslant 4[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Explicación paso a paso:
[tex]5 < 2x + 7 \leqslant 15 \\ 5 - 7 < 2x + 7 - 7 \leqslant 15 - 7 \\ - 2 < 2x \leqslant 8 \\ \frac{ - 2}{2} < \frac{2x}{2} \leqslant \frac{8}{2} \\ - 1 < x \leqslant 4[/tex]