Me podrían explicar como se resuelve...
"Si F(x) =3x^2 entonces cuánto es f(5+h)-f(5)/h"
"Si F(x) =3x^2 entonces cuánto es f(5+h)-f(5)/h"
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f(5 + h) = 3(5 + h)²
= 3(25 + 10h + h²) = 75 + 30h + 3h²
f(5) = 3(5)² = 3(25) = 75
f(5 + h) - f(5) = 75 + 30h + 3h² - 75 = 30h + 3h²
[f(5 + h) - f(5)]/h
[30h + 3h²]/h = 30 + 3h
[f(5 + h) - f(5)]/h = 30 + 3h