35 km/h=..........m/s 28m/s=........km/h 50km/h=........m/s 6m/s=..........km/h Oblicz przyspieszenie ciała,które w ciągu 7 sekund zwiększyło swoją prędkość z o na 100 km/h
basetla
1 km = 1000 m 1 m = 0,001 km 1 h = 3600 s 1 s = 1/3600 h
35 km/h = 35 *1000m/3600s = 9,72 m/s 28 m/s = 28 * 0,001km/(1/3600)h = 100,8 km/h 50 km/h = 50 * 1000m/3600s = 13,89 m/s 6 m/s = 6 * 0,001km/(1/3600)h = 21,6 km/h
1 votes Thanks 1
basetla
Zad. t = 7s, dv = 100 km/h = 27,78 m/s, a = dv/t = 27,78m/s/7s = ok. 3 m/s^2
1 m = 0,001 km
1 h = 3600 s
1 s = 1/3600 h
35 km/h = 35 *1000m/3600s = 9,72 m/s
28 m/s = 28 * 0,001km/(1/3600)h = 100,8 km/h
50 km/h = 50 * 1000m/3600s = 13,89 m/s
6 m/s = 6 * 0,001km/(1/3600)h = 21,6 km/h