Question

2 Autobusty oddalone sa od siebie o 90km jada w taka strone ---> <----

autobuj A jedzie z predkoscia 70km/h a B 90km/h.

1Po jakim czasie sie spodkaja

2jaka droge pokonz kazy z audobusow do spotkania sie

Answer 1

s = 90 km

v1 = 70 km/h

v2 = 90 km/h

 

v = v1 + v2 = 70 + 90 = 160 km/h

v = s / t

t = s / v = 90 / 160 = 0,5625 h = 33 min 45 s

 

s1 = v1 * t = 70 * 0,5625 = 39,378 km

s2 = v2 * t = 90 * 0,5625 = 60,625 km

Answer 2

V1=70km/h

V2=90km/h

Vw=V1+V2

Vw=160km/h

s=90km

 

V=s/t

t=s/Vw

t=90km/160km/h

t=0,5625h

 

s1=V1*t1

s1=70km/h*0,5625h

s1=39,375km

 

s2=V2*t

s2=90km/h*0,5625h

s2=50,625km