[tex]Dane:\\s_1 = 10 \ km\\t_1 = 40 \ min = \frac{40}{60} \ h = \frac{2}{3} \ h\\v_2 = 10\frac{km}{h}\\t_2 = 30 \ min = \frac{1}{2} \ h\\Szukane:\\v_{sr}=?\\\\Rozwiazanie\\\\v_{sr} = \frac{s_{c}}{t_{c}}\\\\s = v\cdot t\\\\s_2 = v_2\cdot t_2 = 10\frac{km}{h}\cdot\frac{1}{2} \ h = 5 \ km[/tex]
[tex]s_{c} = s_1+s_2 = 10 \ km + 5 \ km = 15 \ km\\\\t_{c} = \frac{2}{3} \ h + \frac{1}{2} \ h = \frac{4+3}{6} \ h = \frac{7}{6} \ h\\\\v_{sr} = \frac{15 \ km}{\frac{7}{6} \ h}\\\\\boxed{v_{sr} \approx 12,86\frac{km}{h}}[/tex]
Odp. Średnia prędkość kolarza na całej trasie wynosiła ok. 12,86 km/h.
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[tex]Dane:\\s_1 = 10 \ km\\t_1 = 40 \ min = \frac{40}{60} \ h = \frac{2}{3} \ h\\v_2 = 10\frac{km}{h}\\t_2 = 30 \ min = \frac{1}{2} \ h\\Szukane:\\v_{sr}=?\\\\Rozwiazanie\\\\v_{sr} = \frac{s_{c}}{t_{c}}\\\\s = v\cdot t\\\\s_2 = v_2\cdot t_2 = 10\frac{km}{h}\cdot\frac{1}{2} \ h = 5 \ km[/tex]
[tex]s_{c} = s_1+s_2 = 10 \ km + 5 \ km = 15 \ km\\\\t_{c} = \frac{2}{3} \ h + \frac{1}{2} \ h = \frac{4+3}{6} \ h = \frac{7}{6} \ h\\\\v_{sr} = \frac{15 \ km}{\frac{7}{6} \ h}\\\\\boxed{v_{sr} \approx 12,86\frac{km}{h}}[/tex]
Odp. Średnia prędkość kolarza na całej trasie wynosiła ok. 12,86 km/h.