OJO: 1km = 1000m; lh = 3600s
Por lo tanto: 72km/h = 72(1000m/3600s) = 72(5/18) m/s = 20m/s
Luego:
• Energia cinetica = Ek = (1/2)mV²
→ Ek = (1/2)(500kg)(20m/s)²
→ Ek = 100 000 Joules Respuesta
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OJO: 1km = 1000m; lh = 3600s
Por lo tanto: 72km/h = 72(1000m/3600s) = 72(5/18) m/s = 20m/s
Luego:
• Energia cinetica = Ek = (1/2)mV²
→ Ek = (1/2)(500kg)(20m/s)²
→ Ek = 100 000 Joules Respuesta