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54 km/h=15m/s
a=Δv/Δt
Δv=15-20=-5 m/s
Δt=0,5 s
a=-5:1/28-5*2=-10m/s²
Odp. Opoznienie samochodu jest rowne 10m/s².
Odp. Opóźnienie w tym ruchu wynosi 10 m/s².