w ciągu 1 godziny i 15 min motocyklista przejechał 72 km/h oblicz predkość motocyklisty (w układzie SI)
s = 72km
t = 1h 15min = 1 i 15/60h = 1 i 1/4h = 1,25h
v = s/t
v = 72km/1,25h = 57,6km/h = 16m/s
Pozdrawiam :)
t=1h 15 min = 75 min = 4500 s
s= 72 km = 72000 mv= s/tv=72000m/4500s=16 m/s
v=16m/s
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s = 72km
t = 1h 15min = 1 i 15/60h = 1 i 1/4h = 1,25h
v = s/t
v = 72km/1,25h = 57,6km/h = 16m/s
Pozdrawiam :)
t=1h 15 min = 75 min = 4500 s
s= 72 km = 72000 m
v= s/t
v=72000m/4500s=16 m/s
v=16m/s