Po jakim czasie spadające sfobodnie ciało osiągnie prędkość 90km/h??? Na dzisiaj szybko.
v = 90km/h = 25m/s
zasada zachowania energii
h = v²/2g
h = (25m/s)²/10m/s² x 2 = 31,25s
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Pozdrawiam :)
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v = 90km/h = 25m/s
zasada zachowania energii
h = v²/2g
h = (25m/s)²/10m/s² x 2 = 31,25s
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)