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Dane:
m=180[t]=180000[kg];
t=30[s];
V=360[km/h]/3,6=100[m/s];
Wzory:
F=ma , a=V/t;
F=(m*V)/t;
Jednostka:
[F]=[(kg*m/s)/s]=[N];
Obliczenia;
F=(180000*100)/30=600000[N]=600[kN].
Odp.Siła ciągu wynosi F=600[kN].