Respuesta:
[tex]108 \times \frac{5}{18} = 30[/tex]
[tex]a = \frac{(vf - vi)}{t} \\ a = \frac{(30 - 0)}{10} \\ a = \frac{30}{10} = 3 \frac{m}{ {s}^{2} } [/tex]
La aceleración del móvil es de 3 m/s²
[tex]d = vi \times t + \frac{a \times {t}^{2} }{2} \\ d = 0 \times 10 + \frac{3 \times {10}^{2} }{2} \\ d = \frac{300}{2} \\ d = 150[/tex]
El móvil recorre 150 metros.
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Verified answer
Respuesta:
[tex]108 \times \frac{5}{18} = 30[/tex]
[tex]a = \frac{(vf - vi)}{t} \\ a = \frac{(30 - 0)}{10} \\ a = \frac{30}{10} = 3 \frac{m}{ {s}^{2} } [/tex]
La aceleración del móvil es de 3 m/s²
[tex]d = vi \times t + \frac{a \times {t}^{2} }{2} \\ d = 0 \times 10 + \frac{3 \times {10}^{2} }{2} \\ d = \frac{300}{2} \\ d = 150[/tex]
El móvil recorre 150 metros.