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108 km/hr = 30 m/seg
Tenemos que:
a=(Vf-Vi)/t
La velocidad final es 0, pues detiene se detiene el móvil, entonces:
a=(0-30)/3=-30/3=-10 m/seg^2
La distancia es:
s=(Vf^2-Vo^2)/2a
Sustituimos:
s=(0^2-30^2)/2(10)
s=45 m