Un avión que pesa 330 kg-f, vuela a 6000 m de altura, con una velocidad de 600 km/h. Calcular su energía cinética y potencial
guchiiExplicacion P = 330 kgf h = 6000 m V = 600 km/h = 166.66 m/s Ep = ? Ecs = ? Formula 1 kgf = 9.806 N P = 330 kgf (9.806 N / 1 kgf) = 3235.98 N P = 3235.98 N p = m g m = p / g g = 10 m/s² m = 3235.98 N / 10 m / s² = 323.598 kg Ep = m g h =323.598 kg x 10 m/s² x 6000 m = 19415880 Joule Ec = m v² / 2 = 323.58 kg (166.66 m/s)² / 2 = 4493807.141 Joule
P = 330 kgf
h = 6000 m
V = 600 km/h = 166.66 m/s
Ep = ?
Ecs = ?
Formula
1 kgf = 9.806 N
P = 330 kgf (9.806 N / 1 kgf) = 3235.98 N
P = 3235.98 N
p = m g
m = p / g
g = 10 m/s²
m = 3235.98 N / 10 m / s² = 323.598 kg
Ep = m g h =323.598 kg x 10 m/s² x 6000 m = 19415880 Joule
Ec = m v² / 2 = 323.58 kg (166.66 m/s)² / 2 = 4493807.141 Joule