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s=
u=50km/h (13,89m/s)
v=0
a=
t=6s
Sabemos que:
a=(v-u)/t
a=(0-13,89m/s)/6s
a=-2,3m/s²
Buscamos la distancia:
s=(v+u/2)t
s=(13,89m/s/2)6s
s=41,67m