Respuesta:
52km/h= 14,4m/s
[tex] {vi}^{2} \div ( - 2.d) = a[/tex]
(14,4m/s)²: (-2.30m)=a
-3,45m/s²=a
t= -Vi /a
t= -14,4m/s: (-3,45m/s²)
t= 4,17s
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Respuesta:
52km/h= 14,4m/s
[tex] {vi}^{2} \div ( - 2.d) = a[/tex]
(14,4m/s)²: (-2.30m)=a
-3,45m/s²=a
t= -Vi /a
t= -14,4m/s: (-3,45m/s²)
t= 4,17s