Samochód o masie m=1800 kg przyspiesza od V0 = 0 km/h do predkosci Vk= 80km/h.
a) oblicz energie kinetyczną samochodu przy predkościach podanych:
Wynik zaokrąglij do pełnych dziesiątek kilodżuli.
v(km/h ) 0 ; 20 ; 40 ; 60 ; 70 ; 80
a) oblicz energie kinetyczną samochodu przy predkościach podanych:
Wynik zaokrąglij do pełnych dziesiątek kilodżuli.
v(km/h ) 0 ; 20 ; 40 ; 60 ; 70 ; 80
Isoko
![Szukane :\\E_k = ? \\\\Roziwazanie :\\E_k = \frac{1}{2}mv^2 \\\\E_k_ 1= \frac{1}{2}\cdot 1800\cdot 0 = 0[J]\\\\E_k_ 2= \frac{1}{2}\cdot 1800\cdot 5,5(5) = 5000 [J]\\\\E_k_3 = \frac{1}{2}\cdot 1800\cdot 11,1(1) = 1000[J] = 1[kJ]\\\\E_k_4 = \frac{1}{2}\cdot 1800\cdot 16 \frac{2}{3}= 15000[J]=15[kJ]\\\\E_k_5 = \frac{1}{2}\cdot 1800\cdot 19,4(4) = 17500[J]=17,5[kJ]\\\\E_k_6 = \frac{1}{2}\cdot 1800\cdot 22,2(2) = 20000[J] = 20[kJ]](https://tex.z-dn.net/?f=Szukane+%3A%5C%5CE_k+%3D+%3F+%5C%5C%5C%5CRoziwazanie+%3A%5C%5CE_k+%3D++%5Cfrac%7B1%7D%7B2%7Dmv%5E2+%5C%5C%5C%5CE_k_+1%3D++%5Cfrac%7B1%7D%7B2%7D%5Ccdot+1800%5Ccdot++0+%3D+0%5BJ%5D%5C%5C%5C%5CE_k_+2%3D++%5Cfrac%7B1%7D%7B2%7D%5Ccdot+1800%5Ccdot++5%2C5%285%29+%3D+5000+%5BJ%5D%5C%5C%5C%5CE_k_3+%3D++%5Cfrac%7B1%7D%7B2%7D%5Ccdot+1800%5Ccdot+11%2C1%281%29+%3D+1000%5BJ%5D+%3D+1%5BkJ%5D%5C%5C%5C%5CE_k_4+%3D++%5Cfrac%7B1%7D%7B2%7D%5Ccdot+1800%5Ccdot+16+%5Cfrac%7B2%7D%7B3%7D%3D+15000%5BJ%5D%3D15%5BkJ%5D%5C%5C%5C%5CE_k_5+%3D++%5Cfrac%7B1%7D%7B2%7D%5Ccdot+1800%5Ccdot+19%2C4%284%29+%3D+17500%5BJ%5D%3D17%2C5%5BkJ%5D%5C%5C%5C%5CE_k_6+%3D++%5Cfrac%7B1%7D%7B2%7D%5Ccdot+1800%5Ccdot+22%2C2%282%29+%3D+20000%5BJ%5D+%3D+20%5BkJ%5D "Szukane :\\E_k = ? \\\\Roziwazanie :\\E_k = \frac{1}{2}mv^2 \\\\E_k_ 1= \frac{1}{2}\cdot 1800\cdot 0 = 0[J]\\\\E_k_ 2= \frac{1}{2}\cdot 1800\cdot 5,5(5) = 5000 [J]\\\\E_k_3 = \frac{1}{2}\cdot 1800\cdot 11,1(1) = 1000[J] = 1[kJ]\\\\E_k_4 = \frac{1}{2}\cdot 1800\cdot 16 \frac{2}{3}= 15000[J]=15[kJ]\\\\E_k_5 = \frac{1}{2}\cdot 1800\cdot 19,4(4) = 17500[J]=17,5[kJ]\\\\E_k_6 = \frac{1}{2}\cdot 1800\cdot 22,2(2) = 20000[J] = 20[kJ]")
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