Diketahui fungsi f(x) = x³ - 6x² + 11x - 6 dan g(x) = x² - 5x + 6. Tentukanlah nilai maksimum dan minimum dari fungsi h(x) = f(x) / g(x)!
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DIKETAHUI
[tex]\sf f(x)=x^3-6x^2+11x-6[/tex]
[tex]\sf g(x)=x^2-5x+6[/tex]
[tex]\sf h(x)=\dfrac{f(x)}{g(x)}[/tex]
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DITANYA
[tex]\sf h(x)=...~?[/tex]
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JAWAB
[tex]\begin{aligned}\sf h(x)&=\sf \dfrac{f(x)}{g(x)}\\&=\sf \dfrac{ {x}^{3} - {6x}^2 + 11x -6 }{ {x}^{2} - 5x + 6}\\&=\sf \dfrac{(x - 1)(\bcancel{x - 2})(\bcancel{x - 3})}{(\bcancel{x - 2})(\bcancel{x - 3})}\\&=\sf x - 1\end{aligned}[/tex]