Question

Guys nomor 1,2,3,4,5...
tolong ya...

Answer 1

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Answer 2

1) n(s)= 36
n (A)= (1,4); (2,3); (3,2), (4,1) = 4
P(A)= n(A)/n(S) = 4/36= 1/9
Frekuensi harapan= n x P(A)
...........................= 900×1/9
...........................= 100 <------------ jawaban (d)

2) n(S)= 6
n (A) = 1,2,3,6 = 4
P(A) = n(A)/n(S)= 4/6= 2/3
Frekuensi harapan = n× P(A)
............................= 60×2/3
...........................= 40 kali <----------- jawaban (d)

3) n(S) = 6
n(A) = 2,3,5= 3
P(A) = n(A)/n(S) = 3/6= 1/2
Frekunesi harapan = n×P(A)
............................= 36×1/2
...........................= 18 kali <------------ jawaban (c)

4) n(S) = 8
n(A) = (AAG), (AGA), (AGG), (AAA), (GAA), (GAG), (GGA), (GGG)
Peluang muncul ketiganya angka= P(A) = n(A)/n(S) = 1/8
Frekuensi harapan= n×P(A)
..........................= 80×1/8
.........................= 10 <--------------- jawaban (b)

Yang nomor 5 soalnya terpotong yg ada di photo

Ok?