Respuesta:
Guadalupe
[tex]5 x + 3y = 136 [/tex]
Jesús
[tex]3x + 4y = 108[/tex]
despejando x
[tex]x = \frac{136 - 3y}{5} [/tex]
despejando x en Jesús
[tex]3( \frac{136 - 3y}{5} ) + 4y = 108[/tex]
[tex] \frac{408 - 9y}{5} + 4y = 108[/tex]
[tex] \frac{408}{5} - \frac{9y}{5} + 4y = 108[/tex]
[tex] \frac{ - 9y}{5} + 4y = 108 - \frac{408}{5} [/tex]
[tex] \frac{ - 9y + 20y}{5} = \frac{540 - 408}{5} [/tex]
[tex]5( \frac{ - 9y + 20y}{5} ) = 5( \frac{540 - 408}{5} )[/tex]
se cancelan los 5
[tex] - 9y + 20y = 540 - 408 \\ 11y = 132 \\ y = \frac{132}{11} \\ y = 12[/tex]
cambiando y en x
[tex]x = \frac{136 - 3(12)}{5} = \frac{136 - 36}{5} = \frac{100}{5} = 20[/tex]
probando en 5x+3y=136
[tex]5(20) + 3(12) = 136 \\ 100 + 36 = 136 \\ 136 = 136[/tex]
los tacos cuestan 20 y las tortas 12
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Verified answer
Respuesta:
Guadalupe
[tex]5 x + 3y = 136 [/tex]
Jesús
[tex]3x + 4y = 108[/tex]
despejando x
[tex]x = \frac{136 - 3y}{5} [/tex]
despejando x en Jesús
[tex]3( \frac{136 - 3y}{5} ) + 4y = 108[/tex]
[tex] \frac{408 - 9y}{5} + 4y = 108[/tex]
[tex] \frac{408}{5} - \frac{9y}{5} + 4y = 108[/tex]
[tex] \frac{ - 9y}{5} + 4y = 108 - \frac{408}{5} [/tex]
[tex] \frac{ - 9y + 20y}{5} = \frac{540 - 408}{5} [/tex]
[tex]5( \frac{ - 9y + 20y}{5} ) = 5( \frac{540 - 408}{5} )[/tex]
se cancelan los 5
[tex] - 9y + 20y = 540 - 408 \\ 11y = 132 \\ y = \frac{132}{11} \\ y = 12[/tex]
cambiando y en x
[tex]x = \frac{136 - 3(12)}{5} = \frac{136 - 36}{5} = \frac{100}{5} = 20[/tex]
probando en 5x+3y=136
[tex]5(20) + 3(12) = 136 \\ 100 + 36 = 136 \\ 136 = 136[/tex]
los tacos cuestan 20 y las tortas 12