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2500gr.0,2kal/gr.∆t = 12kj
2500.0,2kal.∆t = 12kj
500kal.∆t = 12kj
∆t = 12kj ÷ 500kal
∆t = 12000j ÷ 2100j
∆t = 5,7
Suhu akhir = 30+5,7
= 35,7°C