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T1= -2 derajat celcius
T2= 12 derajat celcius
C= 0.5 kalori/gr derajat celcius
Q?
Jawab:
Q= m.c. Delta t(t2-t1)
= 500 . 0.5 . (12–2)
= 500 . 0.5 . 10
= 2.500 joule
Maaf klo ada yg salah