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q= 200.0,5.4
= 400 kal
m = 200 g
C = 0,5 kal/g derajat C
Δt = -5 derajat C - -1 derajat C = 4 derajat C
Dit : Q
Jawab :
Q = m . c . Δt
Q = 200 g . 0,5 kal/g derajat C . 4
Q = 400 kal