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syarat turun f'(x) < 0
f'(x) = 0
3x² + 6x - 9 = 0
x² + 2x - 3 = 0
(x - 1)(x + 3) = 0
x = 1 v x = -3
gunakan turunan kedua
jika f''(x) = negatif, titik balik maks
jika f''(x) = positif, titik balik min
f''(x) = 6x + 6
f''(-3) = 6.(-3) + 6 = -12 (titik balik maks)
f''(1) = 6.1 + 6 = 12 (titik balik min)
f(x) turun pada interval -3 < x < 1