Question

Gradien garis yg melalui titik K (p,6) dan (2,-12) adalah 3 , berapa nilai p?

Answer 1

Diketahui     : m = 3, x₁ = p,  x₂ =2, y₁ = 6, y₂ = -12
Ditanyakan  : p ?
Jawab          :
m = y₂ - y₁ / x₂ - x₁
3  = -12 - 6 / 2 - p
3  = -18 / 2-p
3 (2-p) = -18
6 - 3p  = -18
-3p      = -18 - 6
-3p      = -24
p         = 8

Jadi, nilai p adalah 8

Answer 2

(y - y1)/(y2-y1) = (x-x1)/(x2-x1)
(y - 6)/(-12-6) = (x - p)/(2-p)
(y-6)/-18 = ( x - p)/ ( 2 - p)
-18x + 18p = 2y - py - 12 + 6p
2y - py = 12 - 6p - 18x +18 p
y(2-p) = -18x + 12p + 12

m = 3
-18/(2-p) = 3
-18 = 6 - 3p
-24 = -3p
p = 8