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m = 250 gram
c = 0,5 kal/gr°C
Δt = 5°C
L = 80 kal/gr
ditanya
Q
jawab
Q = Q1 + Q2
Q1 = mcΔt
Q1 = 250(0,5)(5)
Q1 = 625 kal
Q2 = mL
Q2 = 250(80)
Q2 = 20000 kal
Q = 625 + 20000 = 20625 kal