Question

Air sebanyak 400 gram pada suhu 100 C dicampur dengan 1,2 kg air pada suhu 20 C. Jika kalor jenis air 1 kal/gr C, maka suhu campurannya adalah....

Answer 1

Diket:
m1 = 400 gram
T1 = 100'c
m2 = 1,2 kg = 1200 gram
t2 = 20'C
c = 1kal/gr'c
Dit: Tc.......?
Qlepas = Qterima
m.c.(t1-tc) = m.c.(tc-t2)
400x1x(100-tc) = 1200x1x(tc-20)
40000 - 400tc = 1200tc - 24000
1200tc+400tc = 40000+24000
1600tc = 64000
tc = 64000/1600
tc = 40"c
suhu campuran 40'c