Question

A.230
B.330
C.350
D.400

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Answer 1

Penjelasan dengan langkah-langkah:

[tex]diketahui : \\ r = 7 \: cm \\ s = 25 \: cm[/tex]

[tex]ditanya : {v}^{kerucut} = ...[/tex]

[tex]jawab : \\ t = \sqrt{ {s}^{2} - {r}^{2} } \\ = \sqrt{ {25}^{2} - {7}^{2} } \\ = \sqrt{625 - 49} \\ = \sqrt{576} \\ = 24 \: cm[/tex]

[tex] {v}^{kerucut} = \frac{1}{3} \times \pi \times {r}^{2} \times t \\ \\ = \frac{1}{3} \times \frac{22}{7} \times {7}^{2} \times 24 \\ \\ = \frac{1}{3} \times \frac{22}{7} \times 49 \times 24 \\ \\ = \frac{1}{3} \times \frac{22}{7} \times 1.176 \\ \\ = \frac{1}{3} \times 3.696 \\ \\ = 1.232 \: {cm}^{3} [/tex]

#maaf kalau salah#

#semoga membantu#

#selamat berpuasa#

Answer 2

Bangun Ruang Sisi Lengkung

[Kerucut]

..

[tex]\begin{aligned} V_{Kerucut} &= ⅓ × π × r² × t \\&= ⅓ × π × r² × \sqrt{s² - r²} \\&= ⅓ × 22/7 × 7² × \sqrt{25² - 7²} \\&= ⅓ × 154 × 24 \\&= 154 × 8 \\&= 1232~cm³ \end{aligned}[/tex]

[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 03 - 04 - 2023}}[/tex]