Question

Gimana nih, tolongin dong.
Thx yah.

Answer 1

Q lepas = Q serap
(k₁ • ΔT₁)/L₁ = (k₂ • ΔT)/L₂
(k • (120 - Tc))/d = (2k • (Tc - 45))/½d
(1 • (120 - Tc))/1= (2 • (Tc - 45))/½
(120 - Tc)= (2Tc - 90)/½
(120 - Tc)= (4Tc - 180)
120 + 180 = 4Tc + Tc
300 = 5Tc
Tc = 60⁰C

Jadi, suhu pada sambungan adalah 60⁰C