Gimana ngerjain ini "Tentukan suhu campuran dari kg air bersuhu 90 derajatC dengan 2kg air bersuhu 60 derajatC" please guys
hidayatNKF
Dik : m1 = 1 kg m2 = 2 kg Δt1 = 90'C Δt2 = 60'C C1 = C2 Dit : t campuran ? Jwb : m1.c1.Δt1 = m2.c2.Δt2 1 kg.(90'C - t campuran) = 2 kg.(t campuran - 60'C) 90kg'C - 1 kg t campuran = 2 kg t ccampuran - 120 kg'C 90kg'C + 120 kg'C = 1 kg t campuran + 2 kg t campuran 210kg'C = 3 kg t campuran t campuran = 210'C / 3 = 70'C
m2 = 2 kg
Δt1 = 90'C
Δt2 = 60'C
C1 = C2
Dit : t campuran ?
Jwb :
m1.c1.Δt1 = m2.c2.Δt2
1 kg.(90'C - t campuran) = 2 kg.(t campuran - 60'C)
90kg'C - 1 kg t campuran = 2 kg t ccampuran - 120 kg'C
90kg'C + 120 kg'C = 1 kg t campuran + 2 kg t campuran
210kg'C = 3 kg t campuran
t campuran = 210'C / 3
= 70'C
maaf ya kalau salah