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(0,7) dan (4,0) --> 7x +4y ≤ 28
(0,5) dan (5,0) --> x + y ≤ 5
cari titik potong kedua garis
7x + 4y = 28
x + y = 5 ......(kalikan 7)
.
7x + 4y = 28
7x + 7y = 35
kurangkan - 3y = -7
y = 7/3
x+ y= 5 --> x = 5 - y
x = 5 - 7/3 = 8/3
titk potong (x,y) = (8/3, 7/3)
nilai f(x,y)= 2x +y
daerah penyelesaian dengan titik pojok
(0,5) -------> f(x,y) = 2(0)+ 1(5) = 5
(8/3, 7/3)--> f(x,y) = 2(8/3) + 1(7/3) = 7 ²/₃
(4,0) -------> f(x,y) = 2(4) + 1(0) = 8
nilai maks = 8