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koordinat awal , saat t = 0
= (4t²+2t+3)i+(3t²+4t+2)j
= (4.(0)² + 2(0) + 3)i + (3(0)² + 4(0) + 2) j
= 3i + 2j
= (3,2) meter
bagian b :
percepatan benda, turunan kedua dari posisi
= d²r/dt
= d²((4t²+2t+3)i+(3t²+4t+2)j) / dt
= 8i + 6j
= √(8² + 6²)
= √100
= 10 m/s²