Question

A calorimeter having a heat capacity of 32cal/C is filled with 100 grams of alcohol whose temperature is 25 C. Into the calorimeter 200 grams of tin at temperature of 100 C is then entered. If the temperature of calorimeter and alcohol increase to be 32,5 C (the specific heat of tin = 0,05 cal/gC), the specific heat of alcohol is.... a. 0.50 cal/gC b. 0,52 cal/gC c. 0,54 cal/gC d 0,56 cal/gC e. 0,58 cal/gC

yang jago fisika bantuin yaa...:)

Answer 1

Sy ksih aja rumus

c1 = 32 kal/C
m1 = 200 gr
m2 = 100 gr
To = 25 C
Tt = 100 C
Tc = 32,5 c

dit. c2
penye.  Qlepas = Qterima
         m1.c1(Tt - To) = m2.c2(Tt - Tc)
masukin aja angkanya n cakar pakai kalkulator

semoga bermanfaat . . . .