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c = 0,21 kal/gr⁰C
m = 0,5 kg = 500 gr
Q = 420 kal
ditan
ΔT
penyelesaian
Q = m . c . ΔT
ΔT =
ΔT =
ΔT = 40
jadi kenaikan suhu yang dialami adalah 40⁰C
jangan lupa di pelajari ya
terbaik