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m= 20 g --> 20/1000= 0,02 kg
Δt= 0-(-4)= 4 °C
C= 0,5 kal/g°C --> 0,5×4,2/0,001= 2100 J/kg°C
Dit:
Q=..?
Penye:
Q= m.C.Δt
Q= 0,02×4×2100
Q= 168 J
t1: -4
dit: Q
jb: Q1: m.c.t
: 20. 0,5.4
:40 j