Explicación:
Q=mcp∆T
[tex]calor = (150gr)(0.35 \frac{cal}{gr \: c} )(90 - 20)c = 3675 \: cal[/tex]
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Explicación:
Q=mcp∆T
[tex]calor = (150gr)(0.35 \frac{cal}{gr \: c} )(90 - 20)c = 3675 \: cal[/tex]