gas propana (C3H8) terbakar sesuai reaksi. C3H3 + 5O2 ➡ 3CO2 + 4H2O. Jika propana yang dibakar 5 liter maka volume gas CO2 yang dihasilkan....Liter.
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Jawaban:
C3H8 + 5O2 ----> 3CO2 + 4H2O
Hukum Gay Lussac :
Perbandingan koefisien = perbandingan Volume
koef propana = 1 = 5L
koef CO2 = 3 = 15 L (pakai berbandingan senilai)