Gas ideal dalm ruang tertutup bersuhu 42 derajat selsius dan tekanan 7 atm serta volumenya 8 liter, apabila gas dipanasi sampai 87derajat selsius ,tekanan naik 1 atm ,maka volume gas
hunaifib
T1 = 42+273 = 315 K T2 = 87+273= 360 K P1 = 700.000 Pa P2 = 800.000 Pa V1 = 0,008 m³
T2 = 87+273= 360 K
P1 = 700.000 Pa
P2 = 800.000 Pa
V1 = 0,008 m³
V2 ?
ANSWER :
P1 V1 / T1 = P2 V2 / T2
700.000 x 0,008 / 315 = 800.000 x V2 /360
315 x 800.000 x V2 = 700.000 x 0,008 x
360
252000000 V2 = 2016000
V2 = 0,008