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• energi dalam
m = 0,44 kg = 440 gr
Mr CO2 = 44 gr/mol
Na = 6,02×10²³
f = 3+4+3 = 10
T = 1227 °C = 1500 K
U = __?
jumlah mol
n = m / Mr
n = 440 / 44 = 10 mol
jumlah partikel
N = n Na
N = 10 • 6,02×10²³ = 6,02×10²⁴
energi dalam
U = N f k T
U = 6,02×10²⁴ • 10 • 1,38×10^-23 • 1500
U = 1246140 J ← jwb