Question

Garis y=px-2 menyinggung kurva y=x^2+x-2.
nilai p adalah...

keterangan : x^2 (x berpangkat 2)

a.3
b.2
c.1
d.0
e.-1

Answer 1

Y = x^2 + x - 2
y = px - 2
x^2 + x - 2 = px - 2
x^2 + x - px = 0
x^2 + (1-p)x = 0
Menyinggung ketika D = 0
(1-p)^2 - 4.1.0 = 0
(1-p)^2 = 0
1-p = 0
p = 1