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mx+1=x^2 +3x+2
0=x^2 + (3-m)x +1
a=1,b=3-m,c=1
karena bersinggungan D =0
b^2 -4ac=0
(3-m)^2 - 4 =0
9 - 6m + m^2 -4 =0
m^2 - 6m + 5 =0
(m-5)(m-1)=0
m1=5,m2=1
nilai 3m-7=8 atau -4