Gradien garis 3x + 6y = 5
m1 =
Karena tegak lurus, maka
m2 = 2
Persamaan garis
⇔ y - y1 = m(x - x1)
⇔ y - 8 = 2(x + 4)
⇔ y - 8 = 2x + 8
⇔ y = 2x + 8 + 8
⇔ 2x + 16 = y
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Gradien garis 3x + 6y = 5
m1 =
m1 =
m1 =
Karena tegak lurus, maka
m2 = 2
Persamaan garis
⇔ y - y1 = m(x - x1)
⇔ y - 8 = 2(x + 4)
⇔ y - 8 = 2x + 8
⇔ y = 2x + 8 + 8
⇔ 2x + 16 = y