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7(y+3)=7(x+4)
y=x+1
a³-b³=(a-b)³+2ab(a-b)
-3a²b+3ab²=-3ab(a-b)
maka
a³-b³-3a²b+3ab²-3²=(a-b)³+3ab(a-b)-3ab(a-b)-3²
⇒(a-b)³=9
tambahan a-b=√3