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Verified answer
MAPEL = MATEMATIKAKELAS = 8
BAB = PERSAMAAN GARIS LURUS
diketahui =
x1 = 5
y1 = -1
tegak lurus dgn -2y = 3x - 4
ditanya = pers.garis??
- mencari gradien
bentuk umum
➡ ax + by + c = 0
m1 = -(a/b)
➡ -2y = 3x - 4
-3x - 2y - 4 = 0
m1 = -(-3/-2)
m1 = 3/-2
karena tegak lurus maka :
m1 . m2 = -1
3/-2 . m2 = -1
m2 = -1 × -2/3
m2 = 2/3
- persamaan garis
semoga membantu
Verified answer
M1 = -3/2x1 = 5
y1 = -1
m = 2/3
tegak lurus :
m2 = 2/3
y-(-1) = 2/3 (x-5)
y+1 = 2/3 (x-5)
3y + 3 = 2x - 10
2x -3y -13 =0