Jawaban:
titik potong dengan sumbu y
y = (0,C)
= (0, -1)
titik potong dengan sumbu x
D = b²-4ac
= (-5²) - 4×(-1)×(-1)
= 100 → D >0
-x²-5x-1
x12 = (- (- 5) plus/minus sqrt((- 5) ^ 2 - 4 * 1(- 1)))/(2 * 1)
x12 = (5 plus/minus sqrt(25 + 4))/2
x1 = (5 + sqrt(29))/2
x2 = (5 - sqrt(29))/2
x1 =(5 + sqrt(29))/2
x2 =(5 - sqrt(29))/2
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Jawaban:
titik potong dengan sumbu y
y = (0,C)
= (0, -1)
titik potong dengan sumbu x
D = b²-4ac
= (-5²) - 4×(-1)×(-1)
= 100 → D >0
-x²-5x-1
x12 = (- (- 5) plus/minus sqrt((- 5) ^ 2 - 4 * 1(- 1)))/(2 * 1)
x12 = (5 plus/minus sqrt(25 + 4))/2
x1 = (5 + sqrt(29))/2
x2 = (5 - sqrt(29))/2
x1 =(5 + sqrt(29))/2
x2 =(5 - sqrt(29))/2