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C = 0,4 kal/goC
DeltaT1 = -12oC
DeltaT2 = -2oC
DeltaT2 - DeltaT1 = -2oC - -12oC=10oC
Ditanyakan = Q?
Jawab = Q=mxCxDeltaT
Q=500x0,4x10oC
Q=2000 kj