Question

F(x)=4x+7 dan fog(x)=4x^2+16x+23
tentukan g^-1(x)

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Answer 1

fog (x) = 4x²+16x+23

4 g(x)+7 = 4x² + 16x + 23

4 g(x) = 4x² + 16x + 16

g(x) = x² + 4x + 4

g(x) = (x+2)²

misal y = (x+2)²

√y = x+2

x = √y - 2

g^-1(x) = √x - 2

Answer 2

Jawab:

Penjelasan dengan langkah-langkah:

4(g(x)) + 7 = 4x² + 16x + 23

4(g(x)) = 4x² + 16x + 16

g(x) = 4x² + 16x + 16 / 4

g(x) = x² + 4x + 4

y = X² + 4x + 4

y = (X+2)²

√y = X+2

X = -2±√y

g^-1(x) = -2±√y

Semoga Membantu ^_^