Penjelasan dengan langkah-langkah:
f(x) = 2x-1
g(x) = x²+3
h(x) = 3x+2
maka
1) (f+g)(x) = 2x-1+x²+3
= x²+2x+2
2) (f+h)(x) = 2x-1+3x+2
= 5x+1
3) (g-f)(x) = x²+3-(2x-1)
=x²-2x+4
4) (h.f)(x) = (3x+2)(2x-1)
= 6x²-3x+4x-2
= 6x²+x-2
5) (g-4)(x) = (x²+3)-4
= x²-1
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Penjelasan dengan langkah-langkah:
f(x) = 2x-1
g(x) = x²+3
h(x) = 3x+2
maka
1) (f+g)(x) = 2x-1+x²+3
= x²+2x+2
2) (f+h)(x) = 2x-1+3x+2
= 5x+1
3) (g-f)(x) = x²+3-(2x-1)
=x²-2x+4
4) (h.f)(x) = (3x+2)(2x-1)
= 6x²-3x+4x-2
= 6x²+x-2
5) (g-4)(x) = (x²+3)-4
= x²-1